def stdDeviation(a):
l=len(a)
m=sum(a)/l
d=0
for i in a:
d+=(i-m)**2
return (d*(1/l))**0.5
a=[5,6,8,9]
print(stdDeviation(a))
========
1.5811388300841898
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Python 自建标准差函数def stdDeviation(a): d+=(i-m)**2 a=[5,6,8,9] Leave a Reply |
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